kayprish/timeoutd
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Remove chk_ssh

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Because the behavior of the function doesn't change at all depending on
whether a utmp entry is over ssh or not, the function which checks this
is not needed, and has been removed.
This commit is contained in:
Petar Kapris 2020-12-31 23:34:40 +01:00
parent 696a3973f1
commit 42731b5ced
1 changed files with 0 additions and 31 deletions
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31
timeoutd.c
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@ -96,8 +96,6 @@ void logoff_msg();
void killit();
int chk_xsession(); /* seppy: is it a X-Session? */
void killit_xsession(); /* seppy: kill the X-Session */
int chk_ssh(pid_t pid); /* seppy: check if user is logged in via ssh (we have to
handle that different... ;( */
char *getusr(pid_t pid); /*seppy: get the owner of a running process */
void segfault(); /* seppy: catch segfault and log them */
int chk_xterm(); /* seppy: is it a xterm? */
@ -964,19 +962,10 @@ char *host;
}
/* check if the pid is sshd. If so, get PID of the child process (another ssh, owned by the user).
Test reverse if this child process is also ssh and owned by the user we want to log out.
(because we don't want to slay another user ;) */
#ifdef DEBUG
syslog(LOG_NOTICE, "I am at killit() pid=%d user=%s line %d", pid, user, __LINE__);
#endif
if (chk_ssh(pid)) {
#ifdef DEBUG
syslog(LOG_NOTICE, "User %s (pid:%d) logged in via ssh from %s.", user, pid, host);
#endif
}
logoff_msg(tty);
sleep(KWAIT); /*make sure msg does not get lost, again (esp. ssh) */
close(tty);
@ -1142,26 +1131,6 @@ char *host, *user;
int chk_ssh(pid) /* seppy; returns true if pid is sshd, otherwise it returns false */
pid_t pid;
{
sprintf(path, "/proc/%d/stat", pid);
proc_file = fopen(path, "r");
if (!proc_file) {
syslog(LOG_WARNING, "chk_ssh(): PID %d does not exist. Something went wrong. Ignoring.",
pid);
return 0;
}
fscanf(proc_file, "%*d (%[^)]", comm);
fclose(proc_file);
if (!strcmp(comm, "sshd"))
return 1;
else
return 0;
}
char *getusr(pid) /*seppy; returns the name of the user owning process with the Process ID pid */
pid_t pid;
{